Ta = 27,000 * a^t
Tb = 1000 * b^t
1.
Ta(t1) = 3Tb(t1)
27,000 * a^t1 = 3000 * b^t1
-->
(b/a)^t1 = 9
t1 = log 9/log (b/a)

2.
3Ta(t2) = Tb(t2)
81,000 * a^t2 = 1000 * b^t2
(b/a)^t2 = 81
t2 = log 81/(log b/a)

כעת נתבונן ביחס:
t1/t2 = (log 9/log (b/a))/log 81/(log b/a) = log 9/log 81;