תודה
y=(ln2x)^2-4ln2xy' = 2[ln (2x)] * (2/2x) - 4*(2/2x) = 2Ln (2x)/x - 4/x
y' = 2[ln (2x)] * (2/2x) - 4*(2/2x) = 2Ln (2x)/x - 4/x